Solve (x-2)(x+1)=(x-1)(x+3 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x-2)(x+1)=(x-1)(x+3$$

Solve for x

$x=\frac{1}{3}\approx 0.333333333$

Steps for Solving Linear Equation

Use the distributive property to multiply $x-2$ by $x+1$ and combine like terms.

$$x^{2}-x-2=\left(x-1\right)\left(x+3\right)$$

Use the distributive property to multiply $x-1$ by $x+3$ and combine like terms.

$$x^{2}-x-2=x^{2}+2x-3$$

Subtract $x^{2}$ from both sides.

$$x^{2}-x-2-x^{2}=2x-3$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$-x-2=2x-3$$

Subtract $2x$ from both sides.

$$-x-2-2x=-3$$

Combine $-x$ and $-2x$ to get $-3x$.

$$-3x-2=-3$$

Add $2$ to both sides.

$$-3x=-3+2$$

Add $-3$ and $2$ to get $-1$.

$$-3x=-1$$

Divide both sides by $-3$.

$$x=\frac{-1}{-3}$$

Fraction $\frac{-1}{-3}$ can be simplified to $\frac{1}{3}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{3}$$