$$(x-2)(x+5)-(x+3)(x-1)=-1$$
$x=6$
$$x^{2}+3x-10-\left(x+3\right)\left(x-1\right)=-1$$
$$x^{2}+3x-10-\left(x^{2}+2x-3\right)=-1$$
$$x^{2}+3x-10-x^{2}-2x+3=-1$$
$$3x-10-2x+3=-1$$
$$x-10+3=-1$$
$$x-7=-1$$
$$x=-1+7$$
$$x=6$$
Show Solution
Hide Solution