Solve (x-2)+(x-3)+(x+9)=0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x-2)+(x-3)+(x+9)=0$$

Solve for x

$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$

Steps for Solving Linear Equation

Combine $x$ and $x$ to get $2x$.

$$2x-2-3+x+9=0$$

Subtract $3$ from $-2$ to get $-5$.

$$2x-5+x+9=0$$

Combine $2x$ and $x$ to get $3x$.

$$3x-5+9=0$$

Add $-5$ and $9$ to get $4$.

$$3x+4=0$$

Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$3x=-4$$

Divide both sides by $3$.

$$x=\frac{-4}{3}$$

Fraction $\frac{-4}{3}$ can be rewritten as $-\frac{4}{3}$ by extracting the negative sign.

$$x=-\frac{4}{3}$$