$$(x-3)(x-4)=(x-5)(x-4)$$
$x=4$
$$x^{2}-7x+12=\left(x-5\right)\left(x-4\right)$$
$$x^{2}-7x+12=x^{2}-9x+20$$
$$x^{2}-7x+12-x^{2}=-9x+20$$
$$-7x+12=-9x+20$$
$$-7x+12+9x=20$$
$$2x+12=20$$
$$2x=20-12$$
$$2x=8$$
$$x=\frac{8}{2}$$
$$x=4$$
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