$$(x-3)(x-4)=(x-5)(x-6)$$
$x = \frac{9}{2} = 4\frac{1}{2} = 4.5$
$$x^{2}-7x+12=\left(x-5\right)\left(x-6\right)$$
$$x^{2}-7x+12=x^{2}-11x+30$$
$$x^{2}-7x+12-x^{2}=-11x+30$$
$$-7x+12=-11x+30$$
$$-7x+12+11x=30$$
$$4x+12=30$$
$$4x=30-12$$
$$4x=18$$
$$x=\frac{18}{4}$$
$$x=\frac{9}{2}$$
Show Solution
Hide Solution
