Solve DC - 3 (x - 3) ^ 2 - x(6c + 4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( x - 3 ) ^ { 2 } - x ( x + 4 )$$

Evaluate

$9-10x$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(x-3\right)^{2}$.

$$x^{2}-6x+9-x\left(x+4\right)$$

Use the distributive property to multiply $x$ by $x+4$.

$$x^{2}-6x+9-\left(x^{2}+4x\right)$$

To find the opposite of $x^{2}+4x$, find the opposite of each term.

$$x^{2}-6x+9-x^{2}-4x$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$-6x+9-4x$$

Combine $-6x$ and $-4x$ to get $-10x$.

$$-10x+9$$

Expand

$9-10x$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(x-3\right)^{2}$.

$$x^{2}-6x+9-x\left(x+4\right)$$

Use the distributive property to multiply $x$ by $x+4$.

$$x^{2}-6x+9-\left(x^{2}+4x\right)$$

To find the opposite of $x^{2}+4x$, find the opposite of each term.

$$x^{2}-6x+9-x^{2}-4x$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$-6x+9-4x$$

Combine $-6x$ and $-4x$ to get $-10x$.

$$-10x+9$$