How to solve (x-y+z)(x+y+z)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x-y+z)(x+y+z) | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x-y+z)(x+y+z)$$

Evaluate

$\left(x+z\right)^{2}-y^{2}$

Solution Steps

Apply the distributive property by multiplying each term of $x-y+z$ by each term of $x+y+z$.

$$x^{2}+xy+xz-yx-y^{2}-yz+zx+zy+z^{2}$$

Combine $xy$ and $-yx$ to get $0$.

$$x^{2}+xz-y^{2}-yz+zx+zy+z^{2}$$

Combine $xz$ and $zx$ to get $2xz$.

$$x^{2}+2xz-y^{2}-yz+zy+z^{2}$$

Combine $-yz$ and $zy$ to get $0$.

$$x^{2}+2xz-y^{2}+z^{2}$$

Show Solution

Expand

$x^{2}+2xz-y^{2}+z^{2}$

Solution Steps

Apply the distributive property by multiplying each term of $x-y+z$ by each term of $x+y+z$.

$$x^{2}+xy+xz-yx-y^{2}-yz+zx+zy+z^{2}$$

Combine $xy$ and $-yx$ to get $0$.

$$x^{2}+xz-y^{2}-yz+zx+zy+z^{2}$$

Combine $xz$ and $zx$ to get $2xz$.

$$x^{2}+2xz-y^{2}-yz+zy+z^{2}$$

Combine $-yz$ and $zy$ to get $0$.

$$x^{2}+2xz-y^{2}+z^{2}$$

Show Solution

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Example

Question

Evaluate

Solution Steps

Expand

Solution Steps