$$(x+1)+\frac{1}{3}(x-1)=\frac{5}{12}(x-2)$$
$x = -\frac{18}{11} = -1\frac{7}{11} \approx -1.636363636$
$$x+1+\frac{1}{3}x+\frac{1}{3}\left(-1\right)=\frac{5}{12}\left(x-2\right)$$
$$x+1+\frac{1}{3}x-\frac{1}{3}=\frac{5}{12}\left(x-2\right)$$
$$\frac{4}{3}x+1-\frac{1}{3}=\frac{5}{12}\left(x-2\right)$$
$$\frac{4}{3}x+\frac{3}{3}-\frac{1}{3}=\frac{5}{12}\left(x-2\right)$$
$$\frac{4}{3}x+\frac{3-1}{3}=\frac{5}{12}\left(x-2\right)$$
$$\frac{4}{3}x+\frac{2}{3}=\frac{5}{12}\left(x-2\right)$$
$$\frac{4}{3}x+\frac{2}{3}=\frac{5}{12}x+\frac{5}{12}\left(-2\right)$$
$$\frac{4}{3}x+\frac{2}{3}=\frac{5}{12}x+\frac{5\left(-2\right)}{12}$$
$$\frac{4}{3}x+\frac{2}{3}=\frac{5}{12}x+\frac{-10}{12}$$
$$\frac{4}{3}x+\frac{2}{3}=\frac{5}{12}x-\frac{5}{6}$$
$$\frac{4}{3}x+\frac{2}{3}-\frac{5}{12}x=-\frac{5}{6}$$
$$\frac{11}{12}x+\frac{2}{3}=-\frac{5}{6}$$
$$\frac{11}{12}x=-\frac{5}{6}-\frac{2}{3}$$
$$\frac{11}{12}x=-\frac{5}{6}-\frac{4}{6}$$
$$\frac{11}{12}x=\frac{-5-4}{6}$$
$$\frac{11}{12}x=\frac{-9}{6}$$
$$\frac{11}{12}x=-\frac{3}{2}$$
$$x=-\frac{3}{2}\times \frac{12}{11}$$
$$x=\frac{-3\times 12}{2\times 11}$$
$$x=\frac{-36}{22}$$
$$x=-\frac{18}{11}$$
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