$$(x+2\frac{3}{4})-4\frac{2}{4}=1\frac{3}{4}$$
$x = \frac{7}{2} = 3\frac{1}{2} = 3.5$
$$4x+2\times 4+3-\left(4\times 4+2\right)=1\times 4+3$$
$$4x+8+3-\left(4\times 4+2\right)=1\times 4+3$$
$$4x+11-\left(4\times 4+2\right)=1\times 4+3$$
$$4x+11-\left(16+2\right)=1\times 4+3$$
$$4x+11-18=1\times 4+3$$
$$4x-7=1\times 4+3$$
$$4x-7=4+3$$
$$4x-7=7$$
$$4x=7+7$$
$$4x=14$$
$$x=\frac{14}{4}$$
$$x=\frac{7}{2}$$
Show Solution
Hide Solution
