Solve (x+3)(x-5)-15=x(x-1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

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a⋅(b-2)=3b

Question

$$(x+3)(x-5)-15=x(x-1)$$

Solve for x

$x=-30$

Steps for Solving Linear Equation

Use the distributive property to multiply $x+3$ by $x-5$ and combine like terms.

$$x^{2}-2x-15-15=x\left(x-1\right)$$

Subtract $15$ from $-15$ to get $-30$.

$$x^{2}-2x-30=x\left(x-1\right)$$

Use the distributive property to multiply $x$ by $x-1$.

$$x^{2}-2x-30=x^{2}-x$$

Subtract $x^{2}$ from both sides.

$$x^{2}-2x-30-x^{2}=-x$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$-2x-30=-x$$

Add $x$ to both sides.

$$-2x-30+x=0$$

Combine $-2x$ and $x$ to get $-x$.

$$-x-30=0$$

Add $30$ to both sides. Anything plus zero gives itself.

$$-x=30$$

Multiply both sides by $-1$.

$$x=-30$$