How to solve (x+3y+4)(5x-2y-3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x+3y+4)(5x-2y-3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x+3y+4)(5x-2y-3)$$

Evaluate

$\left(5x-2y-3\right)\left(x+3y+4\right)$

Solution Steps

Apply the distributive property by multiplying each term of $x+3y+4$ by each term of $5x-2y-3$.

$$5x^{2}-2xy-3x+15yx-6y^{2}-9y+20x-8y-12$$

Combine $-2xy$ and $15yx$ to get $13xy$.

$$5x^{2}+13xy-3x-6y^{2}-9y+20x-8y-12$$

Combine $-3x$ and $20x$ to get $17x$.

$$5x^{2}+13xy+17x-6y^{2}-9y-8y-12$$

Combine $-9y$ and $-8y$ to get $-17y$.

$$5x^{2}+13xy+17x-6y^{2}-17y-12$$

Show Solution

Expand

$5x^{2}+13xy+17x-6y^{2}-17y-12$

Solution Steps

Apply the distributive property by multiplying each term of $x+3y+4$ by each term of $5x-2y-3$.

$$5x^{2}-2xy-3x+15yx-6y^{2}-9y+20x-8y-12$$

Combine $-2xy$ and $15yx$ to get $13xy$.

$$5x^{2}+13xy-3x-6y^{2}-9y+20x-8y-12$$

Combine $-3x$ and $20x$ to get $17x$.

$$5x^{2}+13xy+17x-6y^{2}-9y-8y-12$$

Combine $-9y$ and $-8y$ to get $-17y$.

$$5x^{2}+13xy+17x-6y^{2}-17y-12$$

Show Solution

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