Solve (x + 4) + (2x - 1) + (4x - 8) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x+4)+(2x-1)+(4x-8)$$

Evaluate

$7x-5$

Solution Steps

Combine $x$ and $2x$ to get $3x$.

$$3x+4-1+4x-8$$

Subtract $1$ from $4$ to get $3$.

$$3x+3+4x-8$$

Combine $3x$ and $4x$ to get $7x$.

$$7x+3-8$$

Subtract $8$ from $3$ to get $-5$.

$$7x-5$$

Differentiate w.r.t. x

$7$

Steps Using Derivative Rule for Sum

Combine $x$ and $2x$ to get $3x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+4-1+4x-8)$$

Subtract $1$ from $4$ to get $3$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+3+4x-8)$$

Combine $3x$ and $4x$ to get $7x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(7x+3-8)$$

Subtract $8$ from $3$ to get $-5$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(7x-5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$7x^{1-1}$$

Subtract $1$ from $1$.

$$7x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$7\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$7$$