Solve (x + 5) ^ 2 + (x - 3) ^ 2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x+5)^{2}+(x-3)^{2}$$

Expand

$2x^{2}+4x+34$

Solution Steps

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(x+5\right)^{2}$.

$$x^{2}+10x+25+\left(x-3\right)^{2}$$

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(x-3\right)^{2}$.

$$x^{2}+10x+25+x^{2}-6x+9$$

Combine $x^{2}$ and $x^{2}$ to get $2x^{2}$.

$$2x^{2}+10x+25-6x+9$$

Combine $10x$ and $-6x$ to get $4x$.

$$2x^{2}+4x+25+9$$

Add $25$ and $9$ to get $34$.

$$2x^{2}+4x+34$$

Evaluate

$\left(x+5\right)^{2}+\left(x-3\right)^{2}$

Solution Steps

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(x+5\right)^{2}$.

$$x^{2}+10x+25+\left(x-3\right)^{2}$$

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(x-3\right)^{2}$.

$$x^{2}+10x+25+x^{2}-6x+9$$

Combine $x^{2}$ and $x^{2}$ to get $2x^{2}$.

$$2x^{2}+10x+25-6x+9$$

Combine $10x$ and $-6x$ to get $4x$.

$$2x^{2}+4x+25+9$$

Add $25$ and $9$ to get $34$.

$$2x^{2}+4x+34$$