$$(x+5) \times 6+ { \left(x-3 \right) }^{ 2 }$$
$x^{2}+39$
$$6x+30+\left(x-3\right)^{2}$$
$$6x+30+x^{2}-6x+9$$
$$30+x^{2}+9$$
$$39+x^{2}$$
Show Solution
Hide Solution