Solve (x+6)(x-1)+5=(x)^(2)-6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x+6)(x-1)+5= { x }^{ 2 } -6$$

Solve for x

$x=-1$

Steps for Solving Linear Equation

Use the distributive property to multiply $x+6$ by $x-1$ and combine like terms.

$$x^{2}+5x-6+5=x^{2}-6$$

Add $-6$ and $5$ to get $-1$.

$$x^{2}+5x-1=x^{2}-6$$

Subtract $x^{2}$ from both sides.

$$x^{2}+5x-1-x^{2}=-6$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$5x-1=-6$$

Add $1$ to both sides.

$$5x=-6+1$$

Add $-6$ and $1$ to get $-5$.

$$5x=-5$$

Divide both sides by $5$.

$$x=\frac{-5}{5}$$

Divide $-5$ by $5$ to get $-1$.

$$x=-1$$