$$(x+iy)(1-i)=(2-3i)(-5+5i)( \frac{ -i3 }{ 5 } )$$
$x=9+6i-iy$
$$5\left(x+iy\right)\left(1-i\right)=\left(2-3i\right)\left(-5+5i\right)\left(-i\right)\times 3$$
$$\left(5-5i\right)\left(x+iy\right)=\left(2-3i\right)\left(-5+5i\right)\left(-i\right)\times 3$$
$$\left(5-5i\right)x+\left(5+5i\right)y=\left(2-3i\right)\left(-5+5i\right)\left(-i\right)\times 3$$
$$\left(5-5i\right)x+\left(5+5i\right)y=\left(5+25i\right)\left(-i\right)\times 3$$
$$\left(5-5i\right)x+\left(5+5i\right)y=\left(25-5i\right)\times 3$$
$$\left(5-5i\right)x+\left(5+5i\right)y=75-15i$$
$$\left(5-5i\right)x=75-15i-\left(5+5i\right)y$$
$$\left(5-5i\right)x=75-15i+\left(-5-5i\right)y$$
$$\left(5-5i\right)x=\left(-5-5i\right)y+\left(75-15i\right)$$
$$\frac{\left(5-5i\right)x}{5-5i}=\frac{\left(-5-5i\right)y+\left(75-15i\right)}{5-5i}$$
$$x=\frac{\left(-5-5i\right)y+\left(75-15i\right)}{5-5i}$$
$$x=9+6i-iy$$
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$y=ix+\left(6-9i\right)$
$$\left(5+5i\right)y=75-15i-\left(5-5i\right)x$$
$$\left(5+5i\right)y=75-15i+\left(-5+5i\right)x$$
$$\left(5+5i\right)y=\left(-5+5i\right)x+\left(75-15i\right)$$
$$\frac{\left(5+5i\right)y}{5+5i}=\frac{\left(-5+5i\right)x+\left(75-15i\right)}{5+5i}$$
$$y=\frac{\left(-5+5i\right)x+\left(75-15i\right)}{5+5i}$$
$$y=ix+\left(6-9i\right)$$