How to solve (x+y+1)(x-y+3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (x+y+1)(x-y+3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(x+y+1)(x-y+3)$$

Evaluate

$\left(x-y+3\right)\left(x+y+1\right)$

Solution Steps

Apply the distributive property by multiplying each term of $x+y+1$ by each term of $x-y+3$.

$$x^{2}-xy+3x+yx-y^{2}+3y+x-y+3$$

Combine $-xy$ and $yx$ to get $0$.

$$x^{2}+3x-y^{2}+3y+x-y+3$$

Combine $3x$ and $x$ to get $4x$.

$$x^{2}+4x-y^{2}+3y-y+3$$

Combine $3y$ and $-y$ to get $2y$.

$$x^{2}+4x-y^{2}+2y+3$$

Show Solution

Expand

$x^{2}+4x-y^{2}+2y+3$

Solution Steps

Apply the distributive property by multiplying each term of $x+y+1$ by each term of $x-y+3$.

$$x^{2}-xy+3x+yx-y^{2}+3y+x-y+3$$

Combine $-xy$ and $yx$ to get $0$.

$$x^{2}+3x-y^{2}+3y+x-y+3$$

Combine $3x$ and $x$ to get $4x$.

$$x^{2}+4x-y^{2}+3y-y+3$$

Combine $3y$ and $-y$ to get $2y$.

$$x^{2}+4x-y^{2}+2y+3$$

Show Solution

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Example

Question

Evaluate

Solution Steps

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Solution Steps