$$(x^{2}-3x+5)+(3x^{2}+3x-10)$$
$4x^{2}-5$
$$4x^{2}-3x+5+3x-10$$
$$4x^{2}+5-10$$
$$4x^{2}-5$$
Show Solution
Hide Solution
$8x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{2}-3x+5+3x-10)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{2}+5-10)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{2}-5)$$
$$2\times 4x^{2-1}$$
$$8x^{2-1}$$
$$8x^{1}$$
$$8x$$