Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$(x^{2}+4x)+81=[(\bullet x+4)+3](x+3)$$

Answer

$$u=(x^2+4*x+74-3]x)/(e*l^2*t*x*[b)$$

Solution


Remove parentheses.
x^2+4*x+81=\(bulletx+4+3\)x+3
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
x^2+4*x+81=\(bu{l}^{2}etx+4+3\)x+3
Regroup terms.
x^2+4*x+81=e*u*l^2*t*x*\(b+4+3\)x+3
Simplify  \(eu{l}^{2}tx\(b+4+3\\)  to  \(eu{l}^{2}tx\(b+7+3\\).
x^2+4*x+81=e*u*l^2*t*x*\(b+7+3\)x
Subtract \(7\) from both sides.
x^2+4*x+81-7=e*u*l^2*t*x*\(b+3\)x
Simplify  \({x}^{2}+4x+81-7\)  to  \({x}^{2}+4x+74\).
x^2+4*x+74=e*u*l^2*t*x*\(b+3\)x
Divide both sides by \(e\).
Divide both sides by \({l}^{2}\).
Divide both sides by \(t\).
Divide both sides by \(x\).
Simplify  x)/(e*l^2*t*x))/\(b\)  to  x)/(e*l^2*t*x*\(b\).
Switch sides.
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