$$(x^{3}-23x^{2}+142x-120)\div(x-1)$$
$\left(x-12\right)\left(x-10\right)$
$$\frac{\left(x-12\right)\left(x-10\right)\left(x-1\right)}{x-1}$$
$$\left(x-12\right)\left(x-10\right)$$
$$x^{2}-22x+120$$
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$x^{2}-22x+120$