$$( y + 2 ) ^ { 2 } = 2 ( x + 5 )$$
$x=\frac{\left(y+2\right)^{2}-10}{2}$
$y=-\sqrt{2\left(x+5\right)}-2$
$y=\sqrt{2\left(x+5\right)}-2$
$y=-\sqrt{2\left(x+5\right)}-2$
$y=\sqrt{2\left(x+5\right)}-2\text{, }x\geq -5$
