Solve (y ^ 3 + 3y ^ 2 + 3y + 1) - (y ^ 3 - 3y ^ 2 + 3y - 1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(y^{3}+3y^{2}+3y+1)-(y^{3}-3y^{2}+3y-1)$$

Evaluate

$6y^{2}+2$

Solution Steps

To find the opposite of $y^{3}-3y^{2}+3y-1$, find the opposite of each term.

$$y^{3}+3y^{2}+3y+1-y^{3}+3y^{2}-3y+1$$

Combine $y^{3}$ and $-y^{3}$ to get $0$.

$$3y^{2}+3y+1+3y^{2}-3y+1$$

Combine $3y^{2}$ and $3y^{2}$ to get $6y^{2}$.

$$6y^{2}+3y+1-3y+1$$

Combine $3y$ and $-3y$ to get $0$.

$$6y^{2}+1+1$$

Add $1$ and $1$ to get $2$.

$$6y^{2}+2$$

Expand

$6y^{2}+2$

Solution Steps

To find the opposite of $y^{3}-3y^{2}+3y-1$, find the opposite of each term.

$$y^{3}+3y^{2}+3y+1-y^{3}+3y^{2}-3y+1$$

Combine $y^{3}$ and $-y^{3}$ to get $0$.

$$3y^{2}+3y+1+3y^{2}-3y+1$$

Combine $3y^{2}$ and $3y^{2}$ to get $6y^{2}$.

$$6y^{2}+3y+1-3y+1$$

Combine $3y$ and $-3y$ to get $0$.

$$6y^{2}+1+1$$

Add $1$ and $1$ to get $2$.

$$6y^{2}+2$$