$$(y^{3}+3y^{2}+3y+1)+(y^{3}-3y^{2}+3y-1)$$
$2y\left(y^{2}+3\right)$
$$2y^{3}+3y^{2}+3y+1-3y^{2}+3y-1$$
$$2y^{3}+3y+1+3y-1$$
$$2y^{3}+6y+1-1$$
$$2y^{3}+6y$$
Show Solution
Hide Solution
$$2\left(y^{3}+3y\right)$$
$$y\left(y^{2}+3\right)$$
$$2y\left(y^{2}+3\right)$$