Question

$$( z + 8 ) + \frac { 4 z } { 5 } = - 1 ,$$

Answer

$$f=-(If(z+8)+(4*z)/5)/(e^2*IM*t^2*h^2*n^2*d*v*a*l)$$

Solution


Regroup terms.
\[If(z+8)+\frac{4z}{5}=-tthhnnfdvale\imath e\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[If(z+8)+\frac{4z}{5}=-{t}^{2}{h}^{2}{n}^{2}fdval{e}^{2}\imath \]
Regroup terms.
\[If(z+8)+\frac{4z}{5}=-{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}fdval\]
Divide both sides by \(-{e}^{2}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}}=\imath {t}^{2}{h}^{2}{n}^{2}fdval\]
Divide both sides by \(\imath \).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}}}{\imath }={t}^{2}{h}^{2}{n}^{2}fdval\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}}}{\imath }\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath }\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath }={t}^{2}{h}^{2}{n}^{2}fdval\]
Divide both sides by \({t}^{2}\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath }}{{t}^{2}}={h}^{2}{n}^{2}fdval\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath }}{{t}^{2}}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}}={h}^{2}{n}^{2}fdval\]
Divide both sides by \({h}^{2}\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}}}{{h}^{2}}={n}^{2}fdval\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}}}{{h}^{2}}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}}={n}^{2}fdval\]
Divide both sides by \({n}^{2}\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}}}{{n}^{2}}=fdval\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}}}{{n}^{2}}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}}=fdval\]
Divide both sides by \(d\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}}}{d}=fval\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}}}{d}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}d}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}d}=fval\]
Divide both sides by \(v\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}d}}{v}=fal\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}d}}{v}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dv}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dv}=fal\]
Divide both sides by \(a\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dv}}{a}=fl\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dv}}{a}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dva}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dva}=fl\]
Divide both sides by \(l\).
\[-\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dva}}{l}=f\]
Simplify  \(\frac{\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dva}}{l}\)  to  \(\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dval}\).
\[-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dval}=f\]
Switch sides.
\[f=-\frac{If(z+8)+\frac{4z}{5}}{{e}^{2}\imath {t}^{2}{h}^{2}{n}^{2}dval}\]