Consider $\left(2-x\right)\left(x+2\right)$. Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$. Square $2$.
$$4-x^{2}=x\left(3-x\right)$$
Use the distributive property to multiply $x$ by $3-x$.
$$4-x^{2}=3x-x^{2}$$
Subtract $3x$ from both sides.
$$4-x^{2}-3x=-x^{2}$$
Add $x^{2}$ to both sides.
$$4-x^{2}-3x+x^{2}=0$$
Combine $-x^{2}$ and $x^{2}$ to get $0$.
$$4-3x=0$$
Subtract $4$ from both sides. Anything subtracted from zero gives its negation.
$$-3x=-4$$
Divide both sides by $-3$.
$$x=\frac{-4}{-3}$$
Fraction $\frac{-4}{-3}$ can be simplified to $\frac{4}{3}$ by removing the negative sign from both the numerator and the denominator.
