Solve +10+(-27)+23+(-32)+42 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$+10+(-27)+23+(-32)+42$$

Evaluate

$16$

Solution Steps

Subtract $27$ from $10$ to get $-17$.

$$-17+23-32+42$$

Add $-17$ and $23$ to get $6$.

$$6-32+42$$

Subtract $32$ from $6$ to get $-26$.

$$-26+42$$

Add $-26$ and $42$ to get $16$.

$$16$$

Factor

$2^{4}$