How to solve 8321 + 2534

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8321 + 2534 | Equatix

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Question

$$+ \frac { 8 } { 2 } 3 \frac { 2 } { 5 } - 3 \frac { 1 } { 4 }$$

Evaluate

$\frac{207}{20}=10.35$

Solution Steps

Divide $8$ by $2$ to get $4$.

$$4\times \frac{3\times 5+2}{5}-\frac{3\times 4+1}{4}$$

Multiply $3$ and $5$ to get $15$.

$$4\times \frac{15+2}{5}-\frac{3\times 4+1}{4}$$

Add $15$ and $2$ to get $17$.

$$4\times \frac{17}{5}-\frac{3\times 4+1}{4}$$

Express $4\times \frac{17}{5}$ as a single fraction.

$$\frac{4\times 17}{5}-\frac{3\times 4+1}{4}$$

Multiply $4$ and $17$ to get $68$.

$$\frac{68}{5}-\frac{3\times 4+1}{4}$$

Multiply $3$ and $4$ to get $12$.

$$\frac{68}{5}-\frac{12+1}{4}$$

Add $12$ and $1$ to get $13$.

$$\frac{68}{5}-\frac{13}{4}$$

Least common multiple of $5$ and $4$ is $20$. Convert $\frac{68}{5}$ and $\frac{13}{4}$ to fractions with denominator $20$.

$$\frac{272}{20}-\frac{65}{20}$$

Since $\frac{272}{20}$ and $\frac{65}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{272-65}{20}$$

Subtract $65$ from $272$ to get $207$.

$$\frac{207}{20}$$

Show Solution

Factor

$\frac{3 ^ {2} \cdot 23}{2 ^ {2} \cdot 5} = 10\frac{7}{20} = 10.35$