Question

$$Add:-3,2,1and-4$$

Answer

$$-(A*d^2)/3,2,a*n*d-4$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{Add}{-3},2,1\times and-4\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{A{d}^{2}}{-3},2,1\times and-4\]
Move the negative sign to the left.
\[-\frac{A{d}^{2}}{3},2,1\times and-4\]
Simplify  \(1\times and\)  to  \(and\).
\[-\frac{A{d}^{2}}{3},2,and-4\]