1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve px+n=p | Equatix

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Question

$$px+n=p$$

Solve for p (complex solution)

$\left\{\begin{matrix}p=-\frac{n}{x-1}\text{, }&x\neq 1\\p\in \mathrm{C}\text{, }&n=0\text{ and }x=1\end{matrix}\right.$

Steps for Solving Linear Equation

Subtract $p$ from both sides.

$$px+n-p=0$$

Subtract $n$ from both sides. Anything subtracted from zero gives its negation.

$$px-p=-n$$

Combine all terms containing $p$.

$$\left(x-1\right)p=-n$$

Divide both sides by $x-1$.

$$\frac{\left(x-1\right)p}{x-1}=-\frac{n}{x-1}$$

Dividing by $x-1$ undoes the multiplication by $x-1$.

$$p=-\frac{n}{x-1}$$

Show Solution

Solve for p

$\left\{\begin{matrix}p=-\frac{n}{x-1}\text{, }&x\neq 1\\p\in \mathrm{R}\text{, }&n=0\text{ and }x=1\end{matrix}\right.$

Steps for Solving Linear Equation

Subtract $p$ from both sides.

$$px+n-p=0$$

Subtract $n$ from both sides. Anything subtracted from zero gives its negation.

$$px-p=-n$$

Combine all terms containing $p$.

$$\left(x-1\right)p=-n$$

Divide both sides by $x-1$.

$$\frac{\left(x-1\right)p}{x-1}=-\frac{n}{x-1}$$

Dividing by $x-1$ undoes the multiplication by $x-1$.

$$p=-\frac{n}{x-1}$$

Show Solution

Solve for n

$n=p\left(1-x\right)$

Show Solution

Example

Question

Solve for p (complex solution)

Steps for Solving Linear Equation

Solve for p

Steps for Solving Linear Equation

Solve for n

Solution Steps