$$\quad 14 \frac { 1 } { 6 } - 7 \frac { 1 } { 3 }$$
$\frac{41}{6}\approx 6.833333333$
$$\frac{84+1}{6}-\frac{7\times 3+1}{3}$$
$$\frac{85}{6}-\frac{7\times 3+1}{3}$$
$$\frac{85}{6}-\frac{21+1}{3}$$
$$\frac{85}{6}-\frac{22}{3}$$
$$\frac{85}{6}-\frac{44}{6}$$
$$\frac{85-44}{6}$$
$$\frac{41}{6}$$
Show Solution
Hide Solution
$\frac{41}{2 \cdot 3} = 6\frac{5}{6} = 6.833333333333333$