$$\quad 3 \frac { 1 } { 4 } + 2 \frac { 5 } { 6 } - 4 \frac { 1 } { 3 }$$
$\frac{7}{4}=1.75$
$$\frac{12+1}{4}+\frac{2\times 6+5}{6}-\frac{4\times 3+1}{3}$$
$$\frac{13}{4}+\frac{2\times 6+5}{6}-\frac{4\times 3+1}{3}$$
$$\frac{13}{4}+\frac{12+5}{6}-\frac{4\times 3+1}{3}$$
$$\frac{13}{4}+\frac{17}{6}-\frac{4\times 3+1}{3}$$
$$\frac{39}{12}+\frac{34}{12}-\frac{4\times 3+1}{3}$$
$$\frac{39+34}{12}-\frac{4\times 3+1}{3}$$
$$\frac{73}{12}-\frac{4\times 3+1}{3}$$
$$\frac{73}{12}-\frac{12+1}{3}$$
$$\frac{73}{12}-\frac{13}{3}$$
$$\frac{73}{12}-\frac{52}{12}$$
$$\frac{73-52}{12}$$
$$\frac{21}{12}$$
$$\frac{7}{4}$$
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$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$
