$$\quad 3 ( y - \frac { 1 } { 3 } ) = 2 ( 2 y - 6 )$$
$y=11$
$$3y+3\left(-\frac{1}{3}\right)=2\left(2y-6\right)$$
$$3y-1=2\left(2y-6\right)$$
$$3y-1=4y-12$$
$$3y-1-4y=-12$$
$$-y-1=-12$$
$$-y=-12+1$$
$$-y=-11$$
$$y=11$$
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