$$\quad 4 \frac { 1 } { 3 } + 3 \frac { 1 } { 6 } - 5 \frac { 1 } { 9 } = ?$$
$\frac{43}{18}\approx 2.388888889$
$$\frac{12+1}{3}+\frac{3\times 6+1}{6}-\frac{5\times 9+1}{9}$$
$$\frac{13}{3}+\frac{3\times 6+1}{6}-\frac{5\times 9+1}{9}$$
$$\frac{13}{3}+\frac{18+1}{6}-\frac{5\times 9+1}{9}$$
$$\frac{13}{3}+\frac{19}{6}-\frac{5\times 9+1}{9}$$
$$\frac{26}{6}+\frac{19}{6}-\frac{5\times 9+1}{9}$$
$$\frac{26+19}{6}-\frac{5\times 9+1}{9}$$
$$\frac{45}{6}-\frac{5\times 9+1}{9}$$
$$\frac{15}{2}-\frac{5\times 9+1}{9}$$
$$\frac{15}{2}-\frac{45+1}{9}$$
$$\frac{15}{2}-\frac{46}{9}$$
$$\frac{135}{18}-\frac{92}{18}$$
$$\frac{135-92}{18}$$
$$\frac{43}{18}$$
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$\frac{43}{2 \cdot 3 ^ {2}} = 2\frac{7}{18} = 2.388888888888889$
