How to solve 7/2 + y = - 8/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/2 + y = - 8/3 | Equatix

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$$\quad \frac { 7 } { 2 } + y = - \frac { 8 } { 3 }$$

$y = -\frac{37}{6} = -6\frac{1}{6} \approx -6.166666667$

Subtract $\frac{7}{2}$ from both sides.

$$y=-\frac{8}{3}-\frac{7}{2}$$

Least common multiple of $3$ and $2$ is $6$. Convert $-\frac{8}{3}$ and $\frac{7}{2}$ to fractions with denominator $6$.

$$y=-\frac{16}{6}-\frac{21}{6}$$

Since $-\frac{16}{6}$ and $\frac{21}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$y=\frac{-16-21}{6}$$

Subtract $21$ from $-16$ to get $-37$.

$$y=-\frac{37}{6}$$