How to solve i ) 8/5 / (2/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve i ) 8/5 / (2/3) | Equatix

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$$\quad \frac { 8 } { 5 } \div \frac { 2 } { 3 }$$

$\frac{12}{5}=2.4$

Divide $\frac{8}{5}$ by $\frac{2}{3}$ by multiplying $\frac{8}{5}$ by the reciprocal of $\frac{2}{3}$.

$$\frac{8}{5}\times \frac{3}{2}$$

Multiply $\frac{8}{5}$ times $\frac{3}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 3}{5\times 2}$$

Do the multiplications in the fraction $\frac{8\times 3}{5\times 2}$.

$$\frac{24}{10}$$

Reduce the fraction $\frac{24}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{12}{5}$$

$\frac{2 ^ {2} \cdot 3}{5} = 2\frac{2}{5} = 2.4$