$$\quad ( - 5 k ) + ( - 3 k ) + ( 4 k ) =$$
$-4k$
$$-8k+4k$$
$$-4k$$
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$-4$
$$\frac{\mathrm{d}}{\mathrm{d}k}(-8k+4k)$$
$$\frac{\mathrm{d}}{\mathrm{d}k}(-4k)$$
$$-4k^{1-1}$$
$$-4k^{0}$$
$$-4$$
