$$\quad ( x ) + ( 5 x ) + ( - 5 x ) =$$
$x$
$$6x-5x$$
$$x$$
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$1$
$$\frac{\mathrm{d}}{\mathrm{d}x}(6x-5x)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(x)$$
$$x^{1-1}$$
$$x^{0}$$
$$1$$
