Question

$$R _ { 2 } ( \frac { 5 + 6 i } { 2 } ) + ( 1 - z ) ^ { 2 } = - \frac { 6 - 6 i } { 1 + 1 } + 1 ^ { 26 } + 1 ^ { 10 } + 1 ^ { 10 }$$

Solve for R_2

$R_{2}=\left(-\frac{10}{61}+\frac{12}{61}i\right)\left(1-z\right)^{2}+\left(\frac{36}{61}+\frac{30}{61}i\right)$

Show Solution

Solve for z

$z=\frac{\sqrt{\left(-10-12i\right)R_{2}+12i}}{2}+1$
$z=-\frac{\sqrt{\left(-10-12i\right)R_{2}+12i}}{2}+1$