Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$Rupees6Pasis8$$

Answer

$$48*Ru*e^2*Pa*IM*p*s^3$$

Solution


Take out the constants.
\[(6\times 8)psssRueePa\imath \]
Simplify  \(6\times 8\)  to  \(48\).
\[48psssRueePa\imath \]
Simplify.
\[48p{s}^{3}RueePa\imath \]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[48p{s}^{3}Ru{e}^{2}Pa\imath \]
Regroup terms.
\[48Ru{e}^{2}Pa\imath p{s}^{3}\]
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