Question

$$s\dot{n}=\frac{n}{2}[2a+(n-1)d]$$

Answer

s=(2[2*n*a+d]*(n-1))/(d*o*t*n)

Solution


Regroup terms.
s*d*o*t*n=2\(2na+(n-1)d\)
Regroup terms.
s*d*o*t*n=2\(2na+d\)*(n-1)
Divide both sides by \(d\).
s*o*t*n=(2\(2na+d\)*(n-1))/d
Divide both sides by \(o\).
s*t*n=((2\(2na+d\)*(n-1))/d)/o
Simplify  *(n-1))/d)/o]  to  *(n-1))/(d*o)].
s*t*n=(2\(2na+d\)*(n-1))/(d*o)
Divide both sides by \(t\).
s*n=((2\(2na+d\)*(n-1))/(d*o))/t
Simplify  *(n-1))/(d*o))/t]  to  *(n-1))/(d*o*t)].
s*n=(2\(2na+d\)*(n-1))/(d*o*t)
Divide both sides by \(n\).
s=((2\(2na+d\)*(n-1))/(d*o*t))/n
Simplify  *(n-1))/(d*o*t))/n]  to  *(n-1))/(d*o*t*n)].
s=(2\(2na+d\)*(n-1))/(d*o*t*n)