1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve sin240 | Equatix

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Question

$$\sin 240$$

$-\frac{\sqrt{3}}{2}\approx -0.866025404$

Use $\sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x)$ where $x=180$ and $y=60$ to obtain the result.

$$\sin(180+60)=\sin(180)\cos(60)+\sin(60)\cos(180)$$

Get the value of $\sin(180)$ from trigonometric values table.

$$0\cos(60)+\sin(60)\cos(180)$$

Get the value of $\cos(60)$ from trigonometric values table.

$$0\times \frac{1}{2}+\sin(60)\cos(180)$$

Get the value of $\sin(60)$ from trigonometric values table.

$$0\times \frac{1}{2}+\frac{\sqrt{3}}{2}\cos(180)$$

Get the value of $\cos(180)$ from trigonometric values table.

$$0\times \frac{1}{2}+\frac{\sqrt{3}}{2}\left(-1\right)$$

Do the calculations.

$$-\frac{\sqrt{3}}{2}$$