Question

$$\sin ( { \tan }^{ -1 } 3/4)isqualto$$

Answer

sin(3/(4*tan))*IM*s*q*u*a*l*t*o

Solution


Remove parentheses.
\[\sin{({tan}^{-1}\times \frac{3}{4})}\imath squalto\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\sin{(\frac{1}{tan}\times \frac{3}{4})}\imath squalto\]
Simplify  \(\frac{1}{tan}\times \frac{3}{4}\)  to  \(\frac{3}{4tan}\).
\[\sin{(\frac{3}{4tan})}\imath squalto\]