Question

$$\sin ( x + y ) + y = \cos x$$

Answer

n=(cos(x)-y)/(Si*(x+y))

Solution


Subtract \(y\) from both sides.
\[Sin(x+y)=\cos{x}-y\]
Divide both sides by \(Si\).
\[n(x+y)=\frac{\cos{x}-y}{Si}\]
Divide both sides by \(x+y\).
\[n=\frac{\frac{\cos{x}-y}{Si}}{x+y}\]
Simplify  \(\frac{\frac{\cos{x}-y}{Si}}{x+y}\)  to  \(\frac{\cos{x}-y}{Si(x+y)}\).
\[n=\frac{\cos{x}-y}{Si(x+y)}\]