Question

$$Simpqipy\sqrt{7}\subset3\sqrt{7+\frac{6}{7}}$$

Answer

$$67+21*Si*e*IM*m*p^2*q*y*u*b*s^(3/2)*t$$

Solution


Simplify  \(Simpq\imath py\sqrt{7s}ubset\times 3\sqrt{7}\)  to  \(3Sie\imath mpqpyubst\sqrt{7s\times 7}\).
\[3Sie\imath mpqpyubst\sqrt{7s\times 7}+67\]
Simplify  \(7s\times 7\)  to  \(49s\).
\[3Sie\imath mpqpyubst\sqrt{49s}+67\]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[3Sie\imath mpqpyubst\sqrt{49}\sqrt{s}+67\]
Since \(7\times 7=49\), the square root of \(49\) is \(7\).
\[3Sie\imath mpqpyubst\times 7\sqrt{s}+67\]
Take out the constants.
\[(3\times 7)mppqyubs\sqrt{s}tSie\imath +67\]
Simplify  \(3\times 7\)  to  \(21\).
\[21mppqyubs\sqrt{s}tSie\imath +67\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[21m{p}^{1+1}qyub{s}^{1+\frac{1}{2}}tSie\imath +67\]
Simplify  \(1+1\)  to  \(2\).
\[21m{p}^{2}qyub{s}^{1+\frac{1}{2}}tSie\imath +67\]
Simplify  \(1+\frac{1}{2}\)  to  \(\frac{3}{2}\).
\[21m{p}^{2}qyub{s}^{\frac{3}{2}}tSie\imath +67\]
Regroup terms.
\[21Sie\imath m{p}^{2}qyub{s}^{\frac{3}{2}}t+67\]
Regroup terms.
\[67+21Sie\imath m{p}^{2}qyub{s}^{\frac{3}{2}}t\]