Question

$$!sn^{b_{\perp}}$$

Answer

$$e*n^b*p^2*r*!s$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[!s{n}^{b}{p}^{2}er\]
Regroup terms.
\[e{n}^{b}{p}^{2}r!s\]