$$\sqrt[ 3 ]{ 64 } + \sqrt[ 3 ]{ 8 } + \sqrt[ 2 ]{ 9 }$$
$9$
$$4+\sqrt[3]{8}+\sqrt[2]{9}$$
$$4+2+\sqrt[2]{9}$$
$$6+\sqrt[2]{9}$$
$$6+3$$
$$9$$
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$3^{2}$
