$$\sqrt[3]{1024\cdot108}+0,5\cdot\sqrt[5]{32\cdot243}$$
$51$
$$\sqrt[3]{110592}+0,5\sqrt[5]{32\times 243}$$
$$48+0,5\sqrt[5]{32\times 243}$$
$$48+0,5\sqrt[5]{7776}$$
$$48+0,5\times 6$$
$$48+3$$
$$51$$
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$3\times 17$
