Question

$$\sqrt[3]{-\frac{27a^{3}b^{2}}{c^{6}}}; \sqrt[3]{h^{2}}$$

Answer

$$3^(-c^6/(27*a^3*b^2));3^(1/h^2)$$

Solution


Move the negative sign to the left.
\[\begin{aligned}&{3}^{-\frac{1}{\frac{27{a}^{3}{b}^{2}}{{c}^{6}}}}\\&{\sqrt[h}^{2]{3}}\end{aligned}\]
Invert and multiply.
\[\begin{aligned}&{3}^{-\frac{{c}^{6}}{27{a}^{3}{b}^{2}}}\\&{\sqrt[h}^{2]{3}}\end{aligned}\]