$$\sqrt { [ 12 - 3 \cdot ( 1 + 3 ) ] - 2 + 4 \cdot 2 }$$
$\sqrt{6}\approx 2.449489743$
$$\sqrt{12-3\times 4-2+4\times 2}$$
$$\sqrt{12-12-2+4\times 2}$$
$$\sqrt{0-2+4\times 2}$$
$$\sqrt{-2+4\times 2}$$
$$\sqrt{-2+8}$$
$$\sqrt{6}$$
Show Solution
Hide Solution
