How to solve sqrt(1/6/7 imes4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve sqrt(1/6/7\times4) | Equatix

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$$\sqrt{ 1/6/7 \times 4 }$$

$\frac{\sqrt{42}}{21}\approx 0.3086067$

Express $\frac{\frac{1}{6}}{7}$ as a single fraction.

$$\sqrt{\frac{1}{6\times 7}\times 4}$$

Multiply $6$ and $7$ to get $42$.

$$\sqrt{\frac{1}{42}\times 4}$$

Multiply $\frac{1}{42}$ and $4$ to get $\frac{4}{42}$.

$$\sqrt{\frac{4}{42}}$$

Reduce the fraction $\frac{4}{42}$ to lowest terms by extracting and canceling out $2$.

$$\sqrt{\frac{2}{21}}$$

Rewrite the square root of the division $\sqrt{\frac{2}{21}}$ as the division of square roots $\frac{\sqrt{2}}{\sqrt{21}}$.

$$\frac{\sqrt{2}}{\sqrt{21}}$$

Rationalize the denominator of $\frac{\sqrt{2}}{\sqrt{21}}$ by multiplying numerator and denominator by $\sqrt{21}$.

$$\frac{\sqrt{2}\sqrt{21}}{\left(\sqrt{21}\right)^{2}}$$

The square of $\sqrt{21}$ is $21$.

$$\frac{\sqrt{2}\sqrt{21}}{21}$$

To multiply $\sqrt{2}$ and $\sqrt{21}$, multiply the numbers under the square root.

$$\frac{\sqrt{42}}{21}$$